Select the reagents you would use to synthesize the compounds below from benzene. Use the minimum number of steps. No more than three steps are required in any synthesis. a. Br2, FeBr3

b. CH3COCi. AICl3

c. SO3, H2SO4

d. Cl2, FeCl3

e. KMnO4, H2O

f. HNO3, H2SO4

g. Fe, H3O then OH

h. CH3Cl, AICl3

m-chlorobenzenesulfonic acid:

2,4,6-tribromoaniline

f and a. That is reagents f[HNO3, H2SO4] is used first then followed by reagent a[Br2, FeBr3]

Explanation:

So, in the production of m-bromonitrobenzene[3-Nitro-1-bromobenzene/1-Bromo-3-nitrobenzene] from benzene from the reagents provided by using the fastest reagents that is to say the reagent with the minimum number of steps, we are going to make use of reagents in option 'f' followed by reagents in  option 'a'.

STEP ONE: The first step in the production of m-bromonitrobenzene[3-Nitro-1-bromobenzene/1-Bromo-3-nitrobenzene] from benzene to give the minimum number of steps from the reagents given is nitration by using the reagents in option 'f'' that is  HNO3, H2SO4 to give nitrobenzene. The equation for the chemical reaction is given below as:

C₆H₆ +  HNO₃, H₂SO₄ > C6H5NO2.

It is the N⁺O₂ that is been used in the reaction mechanism [from the reaction:  HNO₃ + H₂SO₄ < > N⁺O₂ + HSO₄⁻ + H₂O].

STEP TWO: The next thing to do is to react the nitrobenzene got from the nitration of benzene in step one above with the reagents in option 'a'[Br2, FeBr3]. This step is known as the bromination of nitrobenzene.

C₆H₅NO₂ + Br₂, FeBr3 > C₆H₄BrNO₂.

the correct option is c.

isotopes refers to different forms of the same element with the same atomic number but different mass number as a result of difference in their neutron numbers. isotopes have different relative atomic mass but share the same chemical properties.