How do you calculate the energy, in joules, of a photon of ultraviolet light with a frequency of 6.8 x 10^15 Hz?

Energy is the quantitative unit, which is measured in joules. The energy of a photon of UV light having the frequency  6.8×10¹⁵ Hz is 45.08×10⁻¹⁹ Joules.

Given:

Frequency of photon = 6.8×10¹⁵ Hz

Energy of a photon in joule =?

Usingt the formula of energy:

E = h x v

where,

v = frequency

h = planck's constant (6.63×10⁻³⁴Js)

E = energy

Substituting the values in the equation, we get:

E = 6.63×10⁻³⁴Js ×6.8×10¹⁵ Hz

E = 6.63×10⁻³⁴Js ×6.8×10¹⁵ s⁻¹

E = 45.08×10⁻¹⁹ Joules

Therefore, the energy of a photon in the UV region is 45.08×10⁻¹⁹ Joules

To know more about energy, refer to the following link:

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E = 45.08×10⁻¹⁹j

Explanation:

Given data:

Energy of photon  in joule = ?

Frequency of photon = 6.8×10¹⁵ Hz

Solution:

Formula:

E = h.f

f = frequency

h = planck's constant (6.63×10⁻³⁴Js)

E = energy

Value of planck's constant is 6.63×10⁻³⁴Js.

E = 6.63×10⁻³⁴Js ×6.8×10¹⁵  Hz

Hz = s⁻¹

E = 6.63×10⁻³⁴Js ×6.8×10¹⁵  s⁻¹

E = 45.08×10⁻¹⁹j

i think that the answer is c