According to the following reaction, how many grams of hydrofluoric acid will be formed upon the complete reaction of 25.6 grams of water with excess silicon tetrafluoride? silicon tetrafluoride (s) + water (l) → hydrofluoric acid (aq) + silicon dioxide (s)

56.89 g of HF

Explanation:

We'll begin by writing the balance equation for the reaction. This is illustrated below:

SiF₄ + 2H₂O —> 4HF + SiO₂

Next, we shall determine the mass of H₂O that reacted and the mass of HF produced from the balanced equation.

This is illustrated:

Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mass of H₂O from the balanced equation = 2 × 18 = 36 g

Molar mass of HF = 1 + 19 = 20 g/mol

Mass of HF from the balanced equation = 4 × 20 = 80 g

Summary:

From the balanced equation above,

36 g of H₂O reacted to produce 80 g of HF.

Finally, we shall determine the mass of HF produced from the reaction. This is illustrated below:

From the balanced equation above,

36 g of H₂O reacted to produce 80 g of HF.

Therefore, 25.6 g of H₂O will react to produce = (25.6 × 80)/36 = 56.89 g of HF.

Thus, 56.89 g of HF were produced from the reaction.

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