A Cu/Cu2 concentration cell has a voltage of 0.22 V at 25 o C. The concentration of Cu2 in one of the half-cells is 1.5 x 10-3 M. What is the concentration of Cu2 in the other half-cell

The concentration is    

Explanation:

From the question we are told that

    The voltage of the cell is  

Generally the reaction at the cathode is  

  the half cell voltage is  V_c =  0.337 V

Generally the reaction at the anode is    

     the half cell voltage is  V_a = -0.337 V

Gnerally the reaction of the cell is  

At initial the voltage is  V  =  0 V

Generally the voltage of the cell at 25°C is  

Here n is number of  of electron and it is 2

So from the question we are told that one cell has a concentration 1.5 x 10-3 M

Let assume it is  

So

=>    

=>  

=>    

=>    

Taking the antilog

=>        

=>      

catya that's not even a b or c

b.false that your answer