If you collect 5.74 mL of O 2 at 298 K and 1.00 atm over 60.0 seconds from a reaction solution of 5.08 mL, what is the initial rate of the reaction

7.71 × 10⁻⁴ M/s

Explanation:

The initial rate of the reaction can be expressed by using the formula:

where the number of moles of O₂ =

where;

Pressue P = 1.00 atm

Volume V =5.74mL =  (5.74 /1000) L

Rate R = 0.082 L atm/mol.K

Temperature = 298 K

= 2.35 × 10⁻⁴ mol

Δ[O₂] =

Δ[O₂] =

Δ[O₂]  = 0.04626 M

The initial rate =

=

= 7.71 × 10⁻⁴ M/s