Neodymium battery + sulfuric acid ——> neodymium sulfate + iron sulfate + boron + hydrogen. I have 5g of Nd2Fe14B and enough H2SO4, how much NdSO4 will I get?

Mass of Nd₂(SO₄)₃ : 2.653 g

Reaction

Nd₂Fe₁₄B + 17H₂SO₄ → Nd₂(SO₄)₃ + 14FeSO₄ + B + 17H₂

5 g Nd₂Fe₁₄B

MW = 2. 144,242 + 14. 55.845 + 10.811

MW = 288.484 + 781.83+10.811=1081.125 g/mol

mol :

mol Nd₂Fe₁₄B = mol Nd₂(SO₄)₃=0.0046

so mass of Nd₂(SO₄)₃ :

MW Nd₂(SO₄)₃ = 2.144.242+3.32,065+12.15,999

MW = 288.484+96.195+191.988=576.667 g/mol

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explanation: