Chemistry, 20.10.2020 14:01 whocares1234
1.00 l sample of polluted water was analysed for lead(II) ions, , by
adding an excess of sodium sulfate to it. The mass of lead(II) sulfate
that precipitated out was 229.8 mg. Calculate the concentration of lead
(II) ions in mg l -1 present in the initial sample of polluted water.
Answers: 1
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1.00 l sample of polluted water was analysed for lead(II) ions, , by
adding an excess of sodium sul...
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