A 10.04-g block of solid tin at 14.77 °C is immersed in a 24.11-g pool of liquid ethylene glycol with a temperature of 63.52 °C. When thermal equilibrium is reached, what is the temperature of the tin and ethylene glycol? Specific heat capacities: tin = 0.213 J/g °C; ethylene glycol = 2.36 J/g °C

61.75 °C

Explanation:

According to the law of conservation of energy,

Qtin = - (Qliquid)

(m×c×∆T)tin = -(m×c×∆T) ethylene glycol

Where; m = mass

c = specific heat capacity

∆T = change in temperature

According to the information given in this question;

For tin: m= 10.04g, c= 0.213 J/g °C, initial temperature= 14.77 °C, final temperature=?

For ethylene glycol: m= 24.11g, c= 2.36 J/g °C, initial temperature= 63.52 °C, final temperature=?

Hence; (m×c×∆T)tin = -(m×c×∆T) ethylene glycol

10.04 × 0.213 × (T - 14.77) = - {24.11 × 2.36 × (T - 63.52)}

2.139 (T - 14.77) = - {56.899 (T - 63.52)}

2.139T - 31.59 = -56.899T + 3614.225

2.139T + 56.899T = 31.59 + 3614.225

59.038T = 3645.815

T = 3645.815/59.038

T = 61.75 °C

The final temperature of tin and ethylene glycol is 61.75 °C

r just means there's a number of carbon in teh chain. for example rcooh means that after x number of carbon, the chain ends with cooh.

explanation:

answer: any goods being imported from another country may be subject to issued by the federal government are tariffs

explanation:  

tariffs are a tax on anything that are imported from abroad. government use them to protect and boost their local industries and the thought is that they encourage consumers to buy local instead of importing and they will hope will protect jobs and economy in the country that implements them