Aluminum metal reacts with chlorine gas to form aluminum chloride. The reaction can be represented by the following balanced chemical equation: 2 Al(s) + 3 Cl2(g) → 2 AlCl3(s).

If you were trying to react 52.9 grams of chlorine gas completely, how many grams of aluminum would you need?

[grams of Aluminum] Do NOT enter the unit in your answer. Report your answer with 3 SFs.

Given to us is the Reaction of Aluminium metal with Chlorine gas . That is ,

Now Mass of 1 mole aluminium = 27g . So mass of 2 moles of it would be 27×2 g = 54g .

Also , Mass of 1 mole of chlorine gas = 35.5 g . So mass of 2 Atoms will be 71g . And mass of 3 moles of atom will be 71 × 3g = 213g .

Now , use unitary method ;

213 g of Chlorine reacts with 54g of Aluminium.

1 g of Chlorine will react with of Aluminium.

Hence 52.9 g of Chlorine will react with = of Aluminium.

6.4 cm (max) - 25 cm (min)