How many milliliters of 10.7 M perchloric acid solution should be used to prepare 5.50 L of 0.200 M

102.8 mL.

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M1) = 10.7 M

Molarity of diluted solution (M2) = 0.2 M

Volume of diluted solution (V2) = 5.5 L

Volume of stock solution needed (V1) =.?

The volume of the stock solution needed can be obtained by using the following formula:

M1V1 = M2V2

10.7 × V2 = 0.2 × 5.5

10.7 × V2 = 1.1

Divide both side by 10.7

V2 = 1.1 / 10.7

V2 = 0.1028 L

Finally, we shall convert 0.1028 L to millilitres (mL) in order to obtain the desired result. This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.1028 L = 0.1028 L × 1000 mL / 1 L

0.1028 L = 102.8 mL

Therefore, 0.1028 L is equivalent to 102.8 mL.

Thus, 102.8 mL of the stock solution (i.e perchloric acid) is needed.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-