What volume will 2.50 mol of hydrogen (H2) occupy at -20.0 °C and 1.5 atm?

v = 34.62 L

Explanation:

Given data:

Moles of H₂ = 2.50 mol

Temperature of gas = -20.0°C

Pressure of gas = 1.5 atm

Volume of gas = ?

Solution:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

-20 + 273 = 253 K

Now we will put the values in formula.

1.5 atm × v = 2.50 mol ×0.0821 atm.L/ mol.K  ×  253 K

1.5 atm × v = 51.93 atm.L

v = 51.93 atm.L/1.5 atm

v = 34.62 L

The volume of hydrogen is 34.62 L.