Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline. 2C8H18+25O2⟶16CO2+18H2O

How many moles of CO2 are emitted into the atmosphere when 16.1 g C8H18 is burned?

NEED ASAP PLEASE.

When 16.1 g of octane burn 1.12 moles of  CO₂ are emitted in atmosphere.

Explanation:

Given data:

Mass of octane C₈H₁₈ = 16.1 g

Moles of CO₂ emitted = ?

Solution:

Chemical equation:

2C₈H₁₈ + 25O₂     →    16CO₂+ 18H₂O

Number of moles of octane:

Number of moles = mass/molar mass

Number of moles = 16.1 g/ 114.23 g/mol

Number of moles = 0.14 mol

Now we will compare the moles of octane with carbon dioxide.

             C₈H₁₈            :              CO₂

                 2               :               16

                0.14           :            16/2×0.14 = 1.12 moles

When 16.1 g of octane burn 1.12 moles of  CO₂ are emitted in atmosphere.