How many moles are there in 17.6 grams of NaOH, sodium hydroxide?

 moles= 0.44moles

Explanation:

Moles = mass/molar mass

Molar mass of NaOH= 23+16+1= 40gmol-1

n= 17.6/40= 0.44 moles

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally