Calculate the maximum mass of potassium sulfate, K2SO4, that could be formed when 4.9 g of sulfuric acid reacts with excess potassium hydroxide. H2SO4 + 2KOH → K2SO4 + 2H2O

From 4.9 g of sulfuric acid 8.175 g of potassium sulfate is formed.

Explanation:

Given data:

Mass of H₂SO₄ = 4.9 g

Mass of K₂SO₄ formed = ?

Solution:

Chemical reaction:

H₂SO₄ + 2KOH    →    K₂SO₄ + 2H₂O

Number of moles of H₂SO₄:

Number of moles = mass/ molar mass

Number of moles = 4.9 g/ 98.1 g/mol

Number of moles = 0.05 mol

Now we will compare the moles of  H₂SO₄ with  K₂SO₄ .

                       H₂SO₄         :             K₂SO₄

                            1             :                  1

                       0.05           :             0.05

Mass of K₂SO₄:

Mass = number of moles × molar mass

Mass = 0.05 mol × 174.3 g/mol

Mass = 8.715 g

Thus, from 4.9 g of sulfuric acid 8.175 g of potassium sulfate is formed.

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