What is the molality of a 10.5% by mass glucose (c6h12o6) the density of the solution is 1.03 g/ml.

Mass water = 100 g solution - 10.5 g glucose => 89.5 g of H2O

Molar mass glucose => 180.1559 g/mol

Molality = moles glucose / kg solvent

( 10.5 / 180.1559 ) mol / ( 89.5 / 1000 ) kg =

0.0582 / 0.0895 => 0.650 mol/kg

hope this helps!

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