Calculate the mass of onygen gas whose
volume is 320mL at 17 degree celsius and 2 atm Pressure

The mass of oxygen will be "0.96 g".

Given:

Volume,

or,

           = 0.32 L

Temperature,

or,

           = 290 K  

Pressure,

General gas constant,

As we know the formula,

→

By substituting the values, we get

hence,

→ Mass of oxygen =      

                               =

                               =

Thus the above answer is right.

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The mass of oxygen gas is 0.96 g.

Explanation:

Given data:

Mass of oxygen gas = ?

Volume of as = 320 mL (320mL × 1L /1000 mL = 0.32 L)

Temperature of gas = 17 °C

Pressure of gas = 2 atm

Solution:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

17+273 = 290 K

Now we will put the values in formula.

2 atm × 0.32 L = n × 0.0821 atm.L/ mol.K   × 290 K

0.64 atm.L =  n × 23.81 atm.L/ mol.

n = 0.64 atm.L / 23.81 atm.L/ mol.

n = 0.03 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.03 mol × 32 g/mol

Mass = 0.96 g

The mass of oxygen gas is 0.96 g.