How many grams of barium chloride (BaCl2) are there in 0.187 mol?
0.187 mol

38.9 grams of

Explanation:

0.187 mol BaCl2 x

0.187 m x 208 g/m

0.187 x 208 g

38.896 g --> 38.9 g BaCl2

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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yes

explanation:

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