For a standard hydrogen atom, how much energy would be released for an electron in the third energy level to fall to the second energy level? Please show all calculations necessary.

The answer is

Explanation:

From the question the energy levels are

n = 3 and n = 2

To calculate the energy released by the electron , we must first calculate the wavelength of the photon emitted by the electron during the transition.

To do so we use Rydberg's equation which is

where

is the wavelength of the emitted photon

R is the Rydberg's constant

= 1.097 × 10^7 m-¹

n2 is the final energy level

n1 is the initial energy level

From the question

n2 = 2 , n1 = 3

So we have

Next we use the formula

To find out the energy emitted

Where

E is the energy

h is the Planck's constant

= 6.626 × 10-³⁴ Js

c is the speed of light which is

3.0 × 10^8 m/s

So we have

We have the final answer as

Hope this helps you

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