Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the piping. However, consider a pipe where water was allowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change, (ΔT), of the water if 210.0 g of water sat in the copper pipe from part A, releasing 3178 J of energy to the pipe? The specific heat of water is 4.184 (J/g)⋅∘C.

-3.617 °C

Explanation:

Step 1: Given data

Mass of water (m): 210.0 g

Energy released in the form of heat (Q): -3178 J (the minus sign corresponds to energy being released)

Specific heat of water (c): 4.184 J/g.°C

Temperature change (ΔT): ?

Step 2: Calculate the temperature change

We will use the following expression.

Q = c × m × ΔT

-3178 J = 4.184 J/g.°C × 210.0 g × ΔT

ΔT = -3.617 °C

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