What is the Theoretical yeild of CaCO3 from 2 g of CaCl2 and 2.5 g of K2CO3

Theoretical yield of CaCO₃ is 2.002 g.

Explanation:

Given data:

Mass of K₂CO₃ = 2.5 g

Mass of CaCl₂ = 2 g

Theoretical yield of CaCO₃ = ?

Solution:

Chemical equation:

K₂CO₃ +  CaCl₂      →     CaCO₃ + 2KCl

Number of moles of K₂CO₃:

Number of moles = mass/molar mass

Number of moles = 2.5 g/ 138.205 g/mol

Number of moles = 0.02 mol

Number of moles of CaCl₂:

Number of moles = mass/molar mass

Number of moles = 2 g/ 110.98 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of CaCO₃ with K₂CO₃ and CaCl₂.

                CaCl₂             :              CaCO₃

                    1                  :                  1

                  0.02              :              0.02

                 K₂CO₃            :               CaCO₃

                     1                 :                   1

                   0.02             :               0.02

Theoretical yield of CaCO₃:

Mass = number of moles × molar mass

Mass = 0.02 mol × 100.1 g/mol

Mass =  2.002 g

Theoretical yield of CaCO₃ is 2.002 g.

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