Carbon-14 is likely to undergo which of the following nuclear decay process, in order to: a)beta decay; to reduce the number of neutrons

b)alpha decay; to increase the number of protons

c)positron emission; to reduce the number of neutrons

d)electron capture; to increase the number of protons

a)beta decay; to reduce the number of neutrons

Explanation:

When an isotope decays by beta decay, a neutron is converted into a proton, an electron and a neutrino (a particle that serves to balance spins). This process reduces the neutron/proton ratio.

During the beta decay of carbon-14, an atom of 14C decays into an atom of 14N. Hence the number of protons in the atom increases by one, creating a nitrogen atom.

i think is conclusions.i think so

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied