In the first propagation step of the bromination of 2,3-dimethylbutane, the newly formed Br radicals react with the molecules of 2,3-dimethylbutane. Give the major products formed by the first propagation step including both organic and inorganic products. Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical.

See explanation

Explanation:

When the bromine free radical attacks 2,3-dimethylbutane, two free radicals may result. One of them is primary (formed by attack on then end -CH3 group) the other is secondary.

Recall that the order of stability of free radicals is tertiary > secondary > primary > methyl.

Hence the secondary free radical is more thermodynamically stable hence it is the major free radical formed in the first propagation step.

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).

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mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b