Substance A has a normal melting point of - 25.0 degrees * C , an enthalpy of fusion of 1200 J g-1; specific heats for the solid and the liquid are 3.00 and 6.20 Jg-1 °C -1, respectively. To change 150 grams of A from a solid at - 40.0 degrees * C to a liquid at + 70.0 degrees * C

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Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

27. =3,500,000 x 4,000 = 14,000,000,000

English , i don't understand spanish.