How much energy will a photon with a frequency of 6.8 x 104 Hz emit?

Energy emitted by photon = 45.06 × 10−32 J

Explanation:

Energy of photon is given by  E = hf

where

h is the Planck's constant whose value is 6.626×10−34J⋅s

f is the frequency of photon

given that

f = 6.8 x 104 Hz

1 HZ = 1 s^-1

E =  6.626×10−34J⋅s * 6.8 x 10^4 Hz

E = 45.06 × 10−32 J

Thus,

Energy emitted by photon is 45.06 × 10−32 J

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