ou are performing a ton test for household ammonia. you place 150 ml of distilled water in a 500 ml beaker first. you added 1 ml of the household ammonia and add distilled water to top up a total volume of 200 ml, the odor can be detected in this dilution. take 50 ml of the above diluted sample as an intermediate sample and continually dilute it to 200 ml and the odor is still detectable. you decided to reduce to 10 ml of the first time diluted household ammonia and the odor was just detectable. how much is the ton of the household ammonia

the ton of the household ammonia is 4000

Explanation:

Given that;

the initial ammonia in 200mL sample = 1ml

also decided to reduce to 10 ml of the first time diluted household ammonia and the odor was just detectable

10ml ammonia content = 1/200 * 10 = 1/20ml

we know that total volume is 200 ml

therefore the TON of household ammonia will be = total volume / volume of ammonia

TON = total volume / volume of ammonia

we substitute

TON = 200 / (1/20)

TON = 200 / 0.05

TON = 4000

therefore the ton of the household ammonia is 4000

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)