How many grams of iron (density = 7.87 g/ml ) would occupy the same volume as 96.4 g of aluminum (density = 2.70 g/ml)?

280.9881 grams of iron.

Explanation:

In order to solve this we first have to calculate the volume of the aluminium because it is the one that we have all of the information to calculate:

Remember that the formula for density is:

We clear it for volume and the result is:

Now we just insert the values:

Now that we have the volume we calculate how many grams of iron we need to occupy that volume, solving the formula for mas:

So the mass of iron needed to cover the same volume as 96.4 g of aluminium would be 280.9881 grams

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explanation:

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