Calculate the specific heat (j/g∘c) for a 18.5-g sample of tin that absorbs 183 j when temperature increases from 35.0 ∘c to 78.6 ∘c.

0.227 J/g°C

Explanation:

Specific heat is the heat change by one gram of substance if it is subjected to change of 1 degree celsius.

The relation between specific heat and mass and change in temperature is:

Q = heat change = mass X specific heat X change in temperature.

Given:

Q = 183 J

Mass = 18.5g

increase in temperature = 78.6-35 = 43.6 °C

Putting values

183 = 18.5X specific heat X 43.6

Specific heat =

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