The average atomic mass of molybdenum (Mo) is 95.94 amu. Which of the following isotopes must have the highest percent abundance?

The two isotopes of Molybdenum have equal natural abundance

Explanation:

= 95.95 amu

x = (95.95 * 2) - 95.94

= 95.96 amu is isotope B, while 95.94amu is isotope A

Using the formula x + (1 - x) = 1

95.96x + 95.94 (1-x) = 95.95

95.96x + 95.94 - 95.94x = 95.95

0.02x = 0.01

x = 0.5

∴ Isotope A and B have equal abundance since 0.5 = 50% abundance.

i hope this was helpful.

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a