2ca3(po4)2 + 6sio2 + 10c --> p4 + 6casio3 + 10co how many grams of calcium phosphate are required to give 30.0g of phosphorus? ? i got 542g but i think that is way off. i did 30g p/30.97g to get .989 moles p • 2ca= 1.94 mole ca• 279.21g to get from miles to grams. explain how to do it and if you can where i went wrong.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :