Amixture is made by combining 1.64 lb of salt and 4.66 lb of water. what is the percentage of salt (by mass) in this mixture?

Answer : The percentage of salt in the mixture is 73.65 %

Explanation : Given,

Mass of salt = 1.64 lb

Mass of water = 4.66 lb

First we have to calculate the mass of mixture.

Mass of mixture = Mass of salt + Mass of water

Mass of mixture = 1.64 + 4.66 = 6.3 lb

Now we have to calculate the percentage of salt in the mixture.

Formula used :

Now put all the given vales in this formula, we get:

Therefore, the percentage of salt in the mixture is 73.65 %

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.