What mass of sulfur has to burn to produce 4.5l so2 at 300°c and 101 kpa in the following reaction?

a. 13.5 g s
b. 3.07 g s
c. 68.8 g s
d. 41.0 g s

The correct answer is option B.

Explanation:

Pressure of the gas = P = 101 kPa = 0.9968 atm

Volume of the gas = V = 4.5 L

Temperature of the gas = T = 300°C = 573.15 K

Moles of sulfur dioxide = n

n = 0.09533 mol

According to reaction , 1 mol sulfur dioxide is obtained from 1 mol of sulfur.

Then 0.09533 mol will be obtained from:

Mass of 0.09533 moles of sulfur = 0.09533 mol × 32 g/mol= 3.07 g

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explanation:

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