How many Aluminum ions are in 4.5 moles of aluminum oxide?

Hat means that 12 g of Al2
2
O3
3
contain 12 g / 101.96 g mol−1
−
1
= 0.118 moles of Al2
2
O3
3
.

Each Al2
2
O3
3
formula unit contains two Al3+
3
+
ions, so there are 2 x 0.118 mol = 0.235 moles of Al3+
3
+
ions.

If you want an actual number, you can multiply that by Avogadro’s constant: 0.235 mol x 6.022 x 1023
23
mol−1
−
1
= 1.42 x 1023
23
ions.

1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)

Answerhave membrane-bound organelles;