If a school uses 1200 gallons/day. How many liters/sec is this?

0.05257 L/s

Explanation:

Step 1: Given data

The school uses 1200 gallons/day

Step 2: Convert "gal/day" to "L/day"

We will use the conversion factor 1 gal = 3.785 L.

1200 gal/day × (3.785L/gal) = 4542 L/day

Step 3: Convert "L/day" to "L/s"

We will use the following conversion factors:

4542 L/day × (1 day/24 h) × (1 h/3600 s) = 0.05257 L/s

i believe the answer is c. "baking" is the gerund, while "baking blueberry muffins" would be the gerund phrase. hope this ! : )

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%