A science class performed an investigation by evaporating a solution containing 10g of salt and 50ml of water. How much salt would you expect to find in the cup at the end of the investigation?

Approximately 10 g due to some experimental errors..

Explanation:

Hello,

In this case, since evaporation accounts for the removal of the solvent of a solution composed by a solvent and a solute via boiling it, we can see here that the solute is the salt and the solvent is the water and by performing an evaporation the 50 mL water need to be boiled; therefore at the end of the experiment, approximately 10 g of the salt are obtained as a solid product, but in some cases we could obtain more than such amount if the evaporation was not complete or less than it if decrepitation (spitting out of the solute due to the heat) occurs as the solid could "jump" out the recipient in which the experiment is carried out.

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answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

explanation:

0.07 g/cm³

1.37 g/cm³