How many moles of carbon are in 90g of glucose(c6h12o6)? assume that the molar mass of glucose is 180g/mol.

We calculate  the number of moles in 90 g of glucose:
180 g1 mol
90 g  x
x=(90 g * 1 mol)/180 g=1/2 moles of glucose

A  molecule of glucose have 6 atoms of  C ;
Therefore
1 mol of glucose have 6 moles of C
But, we have 1/2 moles of glucose therefore:

1 mol of glucose6 moles of C
1/2 mol of glucose  x

x=(1/2 mol of glucose * 6 moles of C) / 1 mol of glucose=3 moles of C

we have 3 moles of C in 90 g of glucose.

Other method:

1)We calculate the number of moles in 90 g of glucose
180 g1 mol
90 g  x

x=(90 g * 1 mol)/180 g=1/2 moles=0.5 moles

2)we calculate the number of molecules  in 0.5 moles of clucose.

1 mol=6.022*10²² molecules
Then:
1 mol6.022*10²³ molecules
0.5 moles  x
x=(0.5 moles * 6.022.10²³ molecules)/1 mol=3.011*10²³ molecules.

3) we calculate the number of atoms in 0.5 moles of glucose.
A molecule of glucose have 6 atoms of C; therefore:
the number of atoms of C =(6 atoms/1 molecule)(3.011*10²³ molecules)=
1.8066*10²⁴

4)We calculate the number of moles of C
atomic mass (C)=12 u
molar mass=12 g/1 mol
1 mol of C=6.022*10²³ atoms of C

Therefore:
1 mol6.022.10²³ atoms of C
x1.8066*10²⁴  atoms of C

x=(1 mol * 1.8066.10²⁴ atoms of C) / 6.022*10²³ atoms of C=
=3

we have 3 moles of C in 90 g of glucose.

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