Carbon monoxide (CO) and hydrogen (H2) are fed to a continuous catalytic reactor operating at steady state. There are no other components in the feed. The outlet stream contains unconverted CO and H2, along with the products methanol (CH30H), ethanol (C2HsOH), isopropanol (C3H70H), and carbon dioxide (C02). These are the only species in the product stream. The reactions occuring are:

CO+ 2H2 → CH3OH
3CO+ 3H2 → C2H5OH+ CO2
5CO+ 4H2 → C3H7OH + 2CO2

The feed rates of CO and H2 to the reactor are 100 mol/h(each). the rates in the stream that leaves the reactor (in mols/h) are H2-30; CO-30; C2H5OH-5. What’s the mole fraction of each species in the product steam?

Explanation:

Let the products in the outlet streams be P(i.e. CH₃OH), Q(i.e. C₂H₅OH) and R(i.e. C₃H₇OH) respectively

Then the mass balance for CO, H and C₂H₅OH can be computed as follows:

For CO, The mass balance is;

100 - P - 3Q - 5R = 30    --- (1)

For H₂, The mass balance is;

100 - 2P - 3Q - 4R = 30    --- (2)

For C₂H₅OH, The mass balance is;

Q = 5    --- (3)

Replacing the value of equation(3) into equation (1) and (2); we have:

From equation (1):

100 - P - 3(5) - 5R = 30    --- (1)

100 - 15 - P - 5R = 30

85 - P - 5R = 30

85 - 30  = P + 5R

P + 5R = 55     (4)

From equation (2):

100 - 2P - 3Q - 4R = 30    --- (2)

100 - 2P - 3(5) - 4R = 30

100 - 15 - 30 = 2P +4R

55 = 2P + 4R

2P + 4R = 55     (5)

From equation (4) and (5); we have:

P + 5R = 55     (4)

2P + 4R = 55     (5)

From equation (4);

Let P = 55 - 5R

Then, replace P = 55 - 5R in equation (5)

2(55 - 5R) + 4R = 55  

110 - 10R + 4R = 55

110 - 6R = 55

6R = 110 - 55

6R = 55

R = 55/6

R = 9.17

Substitute, the value of R in equation (5); we have:

2P + 4R = 55

2P + 4(9.17) = 55

2P  = 55 - 4(9.17)

2P  = 55 - 36.68

2P  =  18.32

P = 18.32/2

P = 9.16

Therefore, the outlet stream rates are as follows:

                  Mass Feed Rate   ( mol/hr)               Molar ratio

CO                  30                                                    0.281

H₂                    30                                                   0.281              

CH₃OH            9.16                                                0.085

C₂H₅OH            5                                                   0.047

C₃H₇OH           9.17                                                0.086

CO₂                 23.34                                              0.219

Total:                106.67

for points guys

sry but any answer choices