Identify the substance oxidized and the substance reduced in the following chemical equation:zn(s)+AgNO3(aq)=Zn(No3)2+2 Ag(a)

Explanation:

zn is oxidized because its oxidation number is increased from zero in zn to +2 in zn(No3)2

Ag is reduced because its oxidation number is reduced from +1 in AgNo3 to zero in Ag

oxidation number of zn(s) is zero while the oxidation number of zn in zn(No3)2  is

zn(No3)2=x+(5*2)+(-2*6)=x+10-12=x-2

x-2+2=2

x=2

the oxidation of Ag in AgNo3

AgNo3=x+5+(3*-2)=x+5-6=x-1

x-1+1=1

x=1 while the oxidation number of Ag is zero

so zinc is oxidized and silver (Ag) is reduced

the objects have the same charge is correct.

nathan lee