At room temperature 20 Celsius and object had a mass of 25g and displaces 15 mL water in a cylinder. what is it’s density? If the object was cooled to point where it had only half of its original thermal energy. What would be it’s temperature in Kelvin and Celsius?

Density = 1.67 g/cm³

New Temperature = 10°C ⇔ 283K

Explanation:

a. Density of a substance can be described as the mass (in grams) of a substance per litre (in mL or cm³) of liquid displaced.

Hence: Density = mass ÷ volume

Density = 25 ÷ 15

Density = 1.67 g/cm³

b. If the object is cooled to half of its original temperature, the new temperature is assumed to be half of the room temperature

Hence, the substance's new temperature will be = 20÷2

=10°C ⇔ 283K (i.e 10 + 273)

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current