QUESTION 17 If the theoretical yield of the following reaction is 3.43g of MgO and the actual yield is 2.48g of Mgo, what is the percent yield?
O 1.38%
O 72.3%
O 0.723%
138%

72.3%

Explanation:

The following data were obtained from the question:

Theoretical yield of MgO = 3.43 g

Actual yield of MgO = 2.48g

Percentage yield of MgO =.?

Percentage yield of a reaction can simply be obtained by dividing the actual yield by the theoretical yield multiplied by 100. This is illustrated below:

Percentage yield = Actual yield /Theoretical yield × 100

Thus, we can obtain the percentage yield of MgO as follow:

Theoretical yield of MgO = 3.43 g

Actual yield of MgO = 2.48g

Percentage yield of MgO =.? Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 2.48/3.43 × 100

Percentage yield = 72.3%

Therefore, the percentage yield of MgO is 72.3%.

the tides are influenced by both the moon and the sun, it's easy to see that when the sun lines up with the moon and the earth, as during a new moon or full moon, the tidal effect is increased. these are known as spring tides, named not for the season, but for the fact that the water "springs" higher than normal. on the other hand, if the sun and the moon are 90 degrees apart in relation to an observer on earth as during the first quarter moon or third quarter moon, then high tides are not as high as they normally would be. this is because despite its greater distance, the sun's mass allows it to exert enough gravitational force on the oceans that it can negate some of the effects of the moon's pull. this phenomenon of lower high tides is called a neap tide. if you need more information on this topic visit moonconnection.com.

i dont know

explanation: