The density of lead, which has the FCC structure, is 11.36 . The atomic weight of lead is 207.19 . Use Avogadro's number: 6.02210. Calculatethe lattice parameter(Enter your answer to three significant figures.) = 2.75*10^21 the atomic radius of lead(Enter your answer to three significant figures.) =

a

b

Explanation:

From the question we are told that

   The  density of  lead is  

   The atomic weight is  

    The  Avogadro's number is  

Generally for FCC the number of  atom is  n  =  4

 Generally the volume of a unit FCC cell is mathematically represented

Generally the lattice parameter is mathematically represented as

=>  

Generally the radius of the lead is mathematically represented as

=>      

=>      

h let me think

what does the table look like