Chemistry, 08.09.2020 14:01 benjamingom030

The volume of a diamond is found to be 2.8 ml. what is the mass of the diamond in carats?

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Answer from: aziah86

49.14 carat.

Explanation:

From the question given above, we obtained the following data:

Volume of diamond = 2.8 mL

Mass of diamond (in carat) =.?

Next, we shall determine the mass of diamond in grams (g). This can be obtained as follow:

Volume of diamond = 2.8 mL

Density of diamond = 3.51 g/mL

Mass of diamond ( in grams) =?

Density = mass /volume

3.51 = mass /2.8

Cross multiply

Mass of diamond (in g) = 3.51 × 2.8

Mass of diamond (in g) = 9.828 g

Finally, we shall Convert 9.828 g to carat. This can be obtained as follow:

1 g = 5 carat

Therefore,

9.828 g = 9.828 g /1 g × 5 carat

9.828 g = 49.14 carat.

Therefore, the mass of the diamond in carat is 49.14 carat.

Answer from: Quest

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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