Draw the structure corresponding to the followingname:. a. (4Z,3S)-2,4,7-trimethyl-3-amino-4-o ctene
b. (3S,6R)-6-(2,4-dinitrophenyl)-3-ami no-1-heptyne

See figures 1 and 2

Explanation:

For this question, we can analyze each compound:

a. (4Z,3S)-2,4,7-trimethyl-3-amino-4-octene

In this case, we have to start with a carbon chain of 8 carbons. Then in carbons 2, 4 and, 7, we have to put three methyl groups (). In carbon 4 we have to put an amino group (). When we put the amino group in carbon 4 we will have a chiral carbon. So, we have to indicate the orientation in the bond of the amino group. If we want an "S" configuration the atoms must have a counterclockwise orientation. So, the amino group must have a dashed bond. Finally, in carbon 4 we have to put a double bond, the configuration of this double bond is "Z". So, the most important groups must be on the same side, in this case.

See figure 1 for further explanations

b. (3S,6R)-6-(2,4-dinitrophenyl)-3-amino-1-heptyne

In this case, we have to start with a chain of 7 carbons. In carbon 3 we have to put an amino group (). When we put this group in carbons we will have a chiral carbon is the name we have an "S" configuration for this carbon. So, we have to use the dashed bond in order to have a counterclockwise orientation for all the atoms bonded on carbon 3. In carbon 6 we have to put a big group "2,4-dinitrophenyl". In this group, we have a bond with the main carbon chain in carbon 6 (of benzene), in this same benzene ring we have to put nitro groups () in carbons 2 and 4. Additionally, carbon 6 is a chiral carbon, and the configuration of this carbon is "R". Therefore we have to use a wedge bond for all the "2,4-dinitrophenyl" in order to have a clockwise orientation for all the atoms bonded on carbon 6. Finally, we have to put a triple bond between carbons 2 and 3.

See figure 2 to further explanations

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