Determine the number of carbon atoms in 1.00 kg of carbon dioxide. X 10__atoms(Enter your answer in scientific notation.)

Determine the number of oxygen atoms in 1.00 kg of carbon dioxide.
X 10__atoms (Enter your answer in scientific notation.)

Calculate the mass of potassium nitrate that contains 1.00 mol of oxygen atoms.
g

—Pls show steps!! I’m so confused and need help—

1. 1.37 * 10^25 atoms of carbon

2. 2.74 * 10^25 atoms of oxygen

3. 33.67g of Potassium Nitrate

Explanation:

2. Firstly, we want to know the number of atoms of oxygen in 1 kg of carbon dioxide.

Firstly, we will need to know the number of moles of carbon iv oxide in 1kg of carbon iv oxide

Mathematically;

number of moles = mass/molar mass

molar mass of carbon iv oxide is 44 g/mol

mass here is 1000g (1kg is 1000g)

So the number of moles of CO2 in 1kg of CO2 will be; 1000/44 = 22.73 moles

Now 1 mole of CO2 contains 2 atoms of oxygen, thus 1 mole of CO2 contains 2 moles of oxygen

So the number of moles of oxygen in 1kg CO2 will be 2 * 22.73 = 45.46 moles

Mathematically, 1 mole contains 6.02 * 10^23 atoms

So 45.46 moles will contain =

6.02 * 10^23 * 45.46 = 2.74 * 10^25 atoms of oxygen

1. 1 mole of co2 contains 1 atom of carbon , thus, 1 mole of CO2 will

contain 1 mole of carbon

From above, 1kg of carbon iv oxide contains 22.73 moles , thus 1kg of carbon iv oxide will contain 22.73 moles of carbon too

So the number of atoms will be 22.73 * 6.02 * 10^23 = 1.37 * 10^25 atoms

3. Mass of KNO3 that contains 1 mole of oxygen atom

From the formula of the compound, we can see that 1 mole of KNO3 contains 3 atoms of oxygen which translates to 3 moles of oxygen

So 1 mole of oxygen will translate to 1/3 mole of KNO3

Mathematically;

mass = number of moles * molar mass

Molar mass of KNO3 = 39 + 14 + 3(16) = 39 + 14 + 48 = 101 g/mol

So the mass will be = 1/3 * 101 = 33.67g

i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8