Which of the following pure compounds will exhibit hydrogen bonding? a.) CH3CH2OH

b.) CH2O

c.) C2H4

d.) C2H2

e.) CH3OCH3

f.) CH3NH2

g.) C3H8

h.) NH3

A, F, H

Explanation:

Hydrogen bonding occurs between compounds that make N-H, O-H, and F-H bonds.  Just because a compound has a N, O, and F atom in the molecule doesn't mean that the compound will exhibit hydrogen bonding.  The N, O, or F must be bonded to a hydrogen.  Carbon-hydrogen bonds do not cause hydrogen bonding.

This means that A, F, and H will have hydrogen bonding.

CH3CH2OH

CH3NH2

NH3

Explanation:

Hydrogen bonds are formed when hydrogen is bonded to an electronegative atom such as oxygen or nitrogen.

Hydrogen bonds accounts for the solubility of alcohols and amines in water. Similarly, it accounts for the high boiling point of ammonia. All the compounds chosen above exhibit a significant degree of hydrogen bonding.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.