At equilibrium, a sample of gas from the system is collected into a 4.00 L flask at 600 K. The flask is found to contain 3.86 g of PCl₅, 12.7 g of PCl₃, and 13.3 g of Cl₂. What are the values of Kc and Kp for this reaction?

Explanation:

                                             PCl₅    ⇄    PCl₃    +     Cl₂

                                           1 mole         1 mole        1 mole

molecular weight of  PCl₅ = 208.5

molecular weight of PCl₃  = 137.5

molecular weight of Cl₂  =       71

moles of PCl₅ = .0185

moles of PCl₃ = .0924

moles of Cl₂ = .1873

Total moles = .2982 moles

mole fraction of PCl₅ = .062

mole fraction of  PCl₃ = .31

mole fraction of Cl₂ = .628

If total pressure be P

partial pressure of  PCl₅ = .062 P

partial pressure of  PCl₃ = .31 P

partial pressure of  Cl₂ = .628 P

Kp = .31 P  x  .628 P /  .062 P

= 3.14 P

To calculate Total pressure P

PV = nRT

P x 4 x 10⁻³ = .2982 x 8.31  x 600

P = 371.7 x 10³

= 3.717 x 10⁵ Pa

Kp = 3.14 P = 3.14 x  3.717 x 10⁵ Pa

= 11.67 x 10⁵ Pa

Kp  = Kc x

= 1

11.67 x 10⁵ = Kc x

Kc = 234

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current