Fill in the blanks below. 1. The equation shows a the breaking and forming of chemical bonds that leads to a change in the composition of matter
2. In the equation, CO2 is a
3. In the equation, C6H1206 is a
4. In O2, the type of bond that holds the two oxygen atoms together is a
5. In H2O, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a
6. The number of oxygen atoms on the left side of the equation is the number of oxygen atoms on the
Chemical equation
right side.
reactant
product
nonpolar
covalent bond
polar
covalent bond
equal to
different from
hydrogen bond

Explanation:

6CO₂ + 6 H₂O ⇄ C₆H₁₂0₆ + 6O₂

This is the chemical equation given .

1. The equation shows a __Chemical equationthe breaking and forming of chemical bonds that leads to a change in the composition of matter.

2. In the equation, CO₂ is a___reactant.

3. In the equation, C₆H₁₂0₆ is a ___product.

4. In O₂, the type of bond that holds the two oxygen atoms together is a_nonpolar_covalent bond.

5. In H₂O, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a__polar_hydrogen bond.

6. The number of oxygen atoms on the left side of the equation is__equal to the number of oxygen atoms on the right side.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol