The combustion of 1.710 g of glucose, C6H12O6(s) , in a bomb calorimeter with a heat capacity of 4.30 kJ/°C results in an increase in the temperature of the calorimeter and its contents from 22.57 °C to 28.77 °C. What is the internal energy change, Δ , for the combustion of 1.710 g of glucose? Δ= kJ Calculate the enthalpy of combustion, Δc , of glucose in kilojoules per mole. Δc= kJ/mol

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

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c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

here are some of the ways in which chemical and nuclear reactions differ.

explanation: