Iron has a density of 7.87mL. How much mass would a 12.3mL sample contain?

The correct answer is 96.80 grams

Explanation:

The density of a substance shows the total mass the substance contains in 1 mL or 1 cm3 as density is calculated by using the formula D= M (mass) / V (volume). This implies, Iron contains 7.87 grams per milliliter. Moreover, this value and formula can be used to calculate the mass or volume of any other sample. The process to calculate the mass of an iron sample with a volume of 12.3 mL is shown below.

D = M ÷ V

7.87 mL = x ÷ 12.3 mL - x represents the missing value. Now find the value of x by solving the equation

x = 7.87 · 12.3  

x = 96.80

This means a sample of 12.3 mL contains a mass of 96.80 grams. Also, you can know this value is correct because if you divide the mass by the value the density is the same (96.80 grams ÷ 12.3 mL = 7.87 g/mL)

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