Chemistry, 27.08.2020 21:01 oksanabkrot
A reaction between 7.0 g of copper(II) oxide and 50 mL of 0.20 M nitric acid produces
copper(II) nitrate, Cu(NO3)2 and water.
(c) Determine the limiting reactant.
(d) Calculate the mass of excess reactant after the reaction.
(ANS: 6.6068g)
(e) Determine the percentage yield if the actual mass of copper (II) nitrate obtained from
the reaction is 0.85 g.
(ANS: 90.64%)
How to get the mass of HNO3 from here? I only managed to get mass of NO3 based on the molarity formula. thanks!
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A reaction between 7.0 g of copper(II) oxide and 50 mL of 0.20 M nitric acid produces
copper(II) ni...
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