Chemistry, 27.08.2020 04:01 kmshacklette9879

Hydrogen peroxide (H2O2, 34 g/mol) decomposes into water vapor and oxygen gas. How many liters of water vapor are produced from the decomposition of 17.0 g of H2O2 at STP?

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Answer from: chanevelyn2

The volume of water vapor produced at STP is 11.60 L.

Explanation:

The decomposition reaction of H₂O₂ is:

2H₂O₂ → O₂ + 2H₂O (1)

We have:

m(H₂O₂): mass = 17.0 g

M(H₂O₂): molar mass = 34 g/mol

To find the volume of water vapor produced we need to find first the number of moles of H₂O₂ and H₂O:

$n_{H_{2}O_{2}} = \frac{m}{M} = \frac{17.0 g}{34 g/mol} = 0.5 moles$

From the reaction (1) we have that 2 moles of H₂O₂ produce 2 moles of H₂O, so the number of moles of H₂O is:

$2n_{H_{2}O_{2}} = 2n_{H_{2}O} \rightarrow n_{H_{2}O} = 0.5 moles$

Now, we can find the volume of water vapor produced at STP, using Ideal gas law:

$V = \frac{nRT}{P} = \frac{0.5 moles*0.085 L*atm/K*mol*273 K}{1 atm} = 11.60 L$

Therefore, the volume of water vapor produced at STP is 11.60 L.

I hope it helps you!

Answer from: Quest

The third choice .. (:

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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